TDC Exam Computer Science Mohan Lal Sukhadia University : Model Question Paper

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Document Described : Mohan Lal Sukhadia University
Model Paper
FIRST YEAR T.D.C. EXAMINATION, 2012
(FACULTY OF SCIENCE)
COMPUTER SCIENCE
Paper I
(Digital Electronics and Introduction to Computer Architecture)
NB : Symbols have their usual meaning.
Time : Three hours Maximum Marks : 75

PART - A [Marks : 45]
Time : One and half hours
Answer all questions. All questions carry equal marks. Each question in this section have answers given as four choices marked as a, b, c, d, out of which only one will be the correct answer.

PART - B [Marks : 30]
Time : One and half hours
Answer any three questions out of five. All questions carry equal marks.

Model Question List : http://mlsu.ac.in/model/B.Sc.html
Model Question Paper : http://mlsu.ac.in/model/Model%20PDF/...CI-PAPER-1.pdf

PART - A
1. The binary number 1101101 is equal to the decimal number
(a) 121 (b) 109
(c) 221 (d) 207

2. The decimal number 58 is equal to the binary number
(a) 100101 (b) 010110
(c) 101001 (d) 111010

3. The 1's complement of 101101001 is
(a) 110010110 (b) 010010010
(c) 010010110 (d) 101100110

4. The 2's complement of 11001000 is
(a) 00110111 (b) 00110110
(c) 00111000 (d) 0011101

5. The decimal number +122 is express in the 2's complement form as
(a) 01111010 (b) 10101111
(c) 11111010 (d) 10011100

6. The decimal number -34 is expressed in the 2's complement form as
(a) 01011110 (b) 10100010
(c) 11011110 (d) 01011101

7. The binary number 10001101010001101111 can be written in hexadecimal as
(a) AD 467 (b) 8C46F
(c) 8D46F (d) AE46F

8. The BCD number for decimal 473 is
(a) 111011010 (b) 110001110011
(c) 010001110011 (d) 010011110011

9. The sum of 11010 + 01111 equals
(a) 101001 (b) 101010
(c) 110101 (d) 101000

10. An inverter performs an operation known as
(a) Complementation (b) Assertion
(c) Inversion (d) Both (a) and (c)

11. The output of a gate is high if and only if all its inputs are low. It is true for
(a) NOR (b) XOR
(c) NAND (d) XNOR

12. The most suitable gate for comparing two bits is
(a) AND (b) NAND
(c) OR (d) XOR